![Cars on display at the 11th annual Gumball 3000 rally race, which kicks off in London and will see participants race through the streets of Amsterdam, Copenhagen, Stockholm, Boston, Quebec City, Toronto Cars on display at the 11th annual Gumball 3000 rally race, which kicks off in London and will see participants race through the streets of Amsterdam, Copenhagen, Stockholm, Boston, Quebec City, Toronto](https://c8.alamy.com/comp/2MR5MM9/cars-on-display-at-the-11th-annual-gumball-3000-rally-race-which-kicks-off-in-london-and-will-see-participants-race-through-the-streets-of-amsterdam-copenhagen-stockholm-boston-quebec-city-toronto-and-new-york-city-the-good-spirited-race-prides-itself-on-not-keeping-timing-scores-and-acts-more-as-a-showcase-for-high-end-sports-cars-an-novelty-automobiles-london-uk-050110-2MR5MM9.jpg)
Cars on display at the 11th annual Gumball 3000 rally race, which kicks off in London and will see participants race through the streets of Amsterdam, Copenhagen, Stockholm, Boston, Quebec City, Toronto
![19 Gumball 3000 10th Anniversary Opening Event Sponsored By Puma Photos and Premium High Res Pictures - Getty Images 19 Gumball 3000 10th Anniversary Opening Event Sponsored By Puma Photos and Premium High Res Pictures - Getty Images](https://media.gettyimages.com/id/82552140/photo/david-hasselhoff-attends-the-gumball-3000-10th-anniversary-opening-event-sponsored-by-puma-at.jpg?s=612x612&w=gi&k=20&c=0E80MMwUF9LHxFqvJ0ovlgriMX-lP_8U6ugfuPf5x7Q=)
19 Gumball 3000 10th Anniversary Opening Event Sponsored By Puma Photos and Premium High Res Pictures - Getty Images
![19 Gumball 3000 10th Anniversary Opening Event Sponsored By Puma Photos and Premium High Res Pictures - Getty Images 19 Gumball 3000 10th Anniversary Opening Event Sponsored By Puma Photos and Premium High Res Pictures - Getty Images](https://media.gettyimages.com/id/93698819/photo/david-hasselhoff-attends-the-gumball-3000-10th-anniversary-opening-event-sponsored-by-puma-at.jpg?s=612x612&w=gi&k=20&c=UOAf6y-_ktqNUgsEUSdhNYI38_MVaesgSwQPIw0aZpk=)